What is the domain of f(x)= x/(sqrt(x-9)) ?

The domain of f(x)= x/(sqrt(x-9)) is x>9

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domain of f(x)= x/(sqrt(x-9))

domain

f (x) = \frac{x}{x - 9}

x > 9

Interval Notation

(9, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 9

Find undefined (singularity) points:

x = 9

Combine real regions and undefined points for final function domain

x > 9

\frac{3}{2 x - 3}

\frac{x - 4}{x ^{3} - 5 x ^{2} + 12 x - 33}

2 - 3 a

y = x 2 - x^{2}

x^{2} + 8

What is the domain of f(x)= x/(sqrt(x-9)) ?
The domain of f(x)= x/(sqrt(x-9)) is x>9