What is the extreme f(x,y)=x^2+2y^2x^2+y^2=1 ?

The extreme f(x,y)=x^2+2y^2x^2+y^2=1 is None

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extreme f(x,y)=x^2+2y^2x^2+y^2=1

extreme points

f (x, y) = x^{2} + 2 y^{2} x^{2} + y^{2} = 1

None

Solution steps

Find the critical points:

None

1

has no critical points, therefore there are no extreme points

None

f (x, y) = e^{x y}

f (x, y) = x^{2} + y

f (x) = x^{3} - 3 x^{2} + 3

f (x, y) = x^{3} + y^{3} - 3 x y

f (x, y) = \frac{1}{x ^{2} + y ^{2} + 1}

What is the extreme f(x,y)=x^2+2y^2x^2+y^2=1 ?
The extreme f(x,y)=x^2+2y^2x^2+y^2=1 is None