What is the domain of f(x)=(sqrt(x-5))/(x-7) ?

The domain of f(x)=(sqrt(x-5))/(x-7) is 5 7

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domain of f(x)=(sqrt(x-5))/(x-7)

domain

f (x) = \frac{x - 5}{x - 7}

5 \leq x < 7 or x > 7

Interval Notation

[5, 7) \cup (7, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 5

Find undefined (singularity) points:

x = 7

Combine real regions and undefined points for final function domain

5 \leq x < 7 or x > 7

\frac{x ^{2} + 1}{2 x ^{2} - 3 x - 2}

14 x - 4 y = 36

\frac{x ^{3}}{9 - x}

P (X) = 2 X^{1} Q (X), (5, 3)

f (x) = - 2 cos (x)

What is the domain of f(x)=(sqrt(x-5))/(x-7) ?
The domain of f(x)=(sqrt(x-5))/(x-7) is 5<= x<7\lor x>7