What is the extreme f(x)=x^3-9x^2+24x-7 ?

The extreme f(x)=x^3-9x^2+24x-7 is Maximum(2,13),Minimum(4,9)

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extreme f(x)=x^3-9x^2+24x-7

extreme points

f (x) = x^{3} - 9 x^{2} + 24 x - 7

Maximum (2, 13), Minimum (4, 9)

Solution steps

f^{'} (x) = 3 x^{2} - 18 x + 24

Find intervals:

Increasing

: - \infty < x < 2,

Decreasing

: 2 < x < 4,

Increasing

: 4 < x < \infty

Plug

x = 2

into

x^{3} - 9 x^{2} + 24 x - 7 : 13

Maximum (2, 13)

Plug

x = 4

into

x^{3} - 9 x^{2} + 24 x - 7 : 9

Minimum (4, 9)

Maximum (2, 13), Minimum (4, 9)

f (x) = \frac{1}{x ^{3} - 6 x ^{2} + 1}

f (x, y) = 1 - x^{2} - 1 - y^{2}

f (x) = x^{3} - 3 x^{2} + 3 x + 1

f (x) = \frac{x}{x ^{2} - 9}

f (x) = x ln (x)

What is the extreme f(x)=x^3-9x^2+24x-7 ?
The extreme f(x)=x^3-9x^2+24x-7 is Maximum(2,13),Minimum(4,9)