What is the extreme f(x)=sqrt(x)+\sqrt[3]{x} ?

The extreme f(x)=sqrt(x)+\sqrt[3]{x} is Minimum(0,0)

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extreme f(x)=sqrt(x)+\sqrt[3]{x}

extreme points

Minimum (0, 0)

Solution steps

f^{'} (x) = \frac{1}{2 x} + \frac{1}{3 x ^{\frac{2}{3}}}

Find intervals:

Increasing

: 0 < x < \infty

Plug

x = 0

into

Minimum (0, 0)

f (x) = 16 - 4 x^{2} - y^{2}

f (x, y) = x^{3} + y^{3} - 3 x - 3 y + 4

F (m, a) = ma

f (x) = 10 + 12 x - 3 x^{2} - 2 x^{3}

f (x) = 3 x y + 12 y x^{5} - 3

What is the extreme f(x)=sqrt(x)+\sqrt[3]{x} ?
The extreme f(x)=sqrt(x)+\sqrt[3]{x} is Minimum(0,0)