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Popular >

extreme f(x)=x^2+2x

Solution

extreme points

f (x) = x^{2} + 2 x

Solution

Minimum (- 1, - 1)

Solution steps

f^{'} (x) = 2 x + 2

Find intervals:

Decreasing

: - \infty < x < - 1,

Increasing

: - 1 < x < \infty

Plug

x = - 1

into

x^{2} + 2 x : - 1

Minimum (- 1, - 1)

Popular Examples

extreme f(x,y)=x^2y-x^2-2y^2 extreme points

f (x, y) = x^{2} y - x^{2} - 2 y^{2}

extreme f(x)=2x^3+9x^2+12x+1 extreme points

f (x) = 2 x^{3} + 9 x^{2} + 12 x + 1

extreme f(x)=3x^4-4x^3 extreme points

f (x) = 3 x^{4} - 4 x^{3}

extreme g(x,y)=sqrt(9-x^2-y^2)extreme points

g (x, y) = 9 - x^{2} - y^{2}

extreme f(x)=(x^2)/(x^2-1)extreme points

f (x) = \frac{x ^{2}}{x ^{2} - 1}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2+2x ?
The extreme f(x)=x^2+2x is Minimum(-1,-1)