What is the extreme f(x)=-3x^5+5x^3 ?

The extreme f(x)=-3x^5+5x^3 is Minimum(-1,-2),Saddle(0,0),Maximum(1,2)

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extreme f(x)=-3x^5+5x^3

extreme points

f (x) = - 3 x^{5} + 5 x^{3}

Minimum (- 1, - 2), Saddle (0, 0), Maximum (1, 2)

Solution steps

f^{'} (x) = - 15 x^{4} + 15 x^{2}

Find intervals:

Decreasing

: - \infty < x < - 1,

Increasing

: - 1 < x < 0,

Increasing

: 0 < x < 1,

Decreasing

: 1 < x < \infty

Plug

x = - 1

into

- 3 x^{5} + 5 x^{3} : - 2

Minimum (- 1, - 2)

Plug

x = 0

into

- 3 x^{5} + 5 x^{3} : 0

Saddle (0, 0)

Plug

x = 1

into

- 3 x^{5} + 5 x^{3} : 2

Maximum (1, 2)

Minimum (- 1, - 2), Saddle (0, 0), Maximum (1, 2)

f (x) = x 9 - x^{2}

f (x, y) = y - x

f (x) = 2 x^{3} + 3 x^{2} + 12 x - 4

f (x) = (2 - x)^{3}

f (x, y) = x^{3} + y^{3} - 3 x^{2} - 3 y^{2} - 9 x

What is the extreme f(x)=-3x^5+5x^3 ?
The extreme f(x)=-3x^5+5x^3 is Minimum(-1,-2),Saddle(0,0),Maximum(1,2)