What is the extreme f(x)=2x^3-3x^2 ?

The extreme f(x)=2x^3-3x^2 is Maximum(0,0),Minimum(1,-1)

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extreme f(x)=2x^3-3x^2

extreme points

f (x) = 2 x^{3} - 3 x^{2}

Maximum (0, 0), Minimum (1, - 1)

Solution steps

f^{'} (x) = 6 x^{2} - 6 x

Find intervals:

Increasing

: - \infty < x < 0,

Decreasing

: 0 < x < 1,

Increasing

: 1 < x < \infty

Plug

x = 0

into

2 x^{3} - 3 x^{2} : 0

Maximum (0, 0)

Plug

x = 1

into

2 x^{3} - 3 x^{2} : - 1

Minimum (1, - 1)

Maximum (0, 0), Minimum (1, - 1)

f (x, y) = x e^{y}

f (x, y) = \frac{1}{16 - x ^{2} - y ^{2}}

f (x) = 100 + \frac{1}{2} x + \frac{1800}{x}

f (x) = \frac{x}{x ^{2} - 9}

f (x) = 2 x^{3} - 3 x^{2} - 12 x + 1, - 2 \leq x \leq 3

What is the extreme f(x)=2x^3-3x^2 ?
The extreme f(x)=2x^3-3x^2 is Maximum(0,0),Minimum(1,-1)