What is the extreme f(x)=sqrt(1-x^2) ?

The extreme f(x)=sqrt(1-x^2) is Minimum(-1,0),Maximum(0,1),Minimum(1,0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=sqrt(1-x^2)

extreme points

f (x) = 1 - x^{2}

Minimum (- 1, 0), Maximum (0, 1), Minimum (1, 0)

Solution steps

f^{'} (x) = - \frac{x}{1 - x ^{2}}

Find intervals:

Increasing

: - 1 < x < 0,

Decreasing

: 0 < x < 1

Plug

x = - 1

into

1 - x^{2} : 0

Minimum (- 1, 0)

Plug

x = 0

into

1 - x^{2} : 1

Maximum (0, 1)

Plug

x = 1

into

1 - x^{2} : 0

Minimum (1, 0)

Minimum (- 1, 0), Maximum (0, 1), Minimum (1, 0)

f (x, y) = 4 x^{2} y + 2 x y^{2} - 12 x y - 5

f (x) = x^{3} + \frac{48}{x}

f (x, y) = \frac{y ^{2}}{y + x ^{2}}

f (x) = \frac{1}{3} x^{3} + \frac{1}{2} x^{2} - 6 x + 8

f (x) = x^{\frac{2}{3}}

What is the extreme f(x)=sqrt(1-x^2) ?
The extreme f(x)=sqrt(1-x^2) is Minimum(-1,0),Maximum(0,1),Minimum(1,0)