What is the extreme f(x,y)=9-2x+4y-x^2-4y^2 ?

The extreme f(x,y)=9-2x+4y-x^2-4y^2 is Maximum(-1, 1/2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x,y)=9-2x+4y-x^2-4y^2

extreme points

f (x, y) = 9 - 2 x + 4 y - x^{2} - 4 y^{2}

Maximum (- 1, \frac{1}{2})

Solution steps

Find the critical points:

(- 1, \frac{1}{2})

\frac{\partial ^{2} f}{\partial x ^{2}} = - 8

D (x, y) = 16

Check the sign of at each critical point

Check critical point

(- 1, \frac{1}{2}) :

Maximum

Maximum (- 1, \frac{1}{2})

f (x) = x^{2} e^{- x}, - 1 \leq x \leq 1

f (x) = x^{4} + 4 x^{3} - 2

f (x, y) = 36 - 9 x^{2} - 4 y^{2}

f (x) = - x^{3} + 2 x^{2}

f (x, y) = (x^{2} + y^{2}) \cdot e^{- x - y}

What is the extreme f(x,y)=9-2x+4y-x^2-4y^2 ?
The extreme f(x,y)=9-2x+4y-x^2-4y^2 is Maximum(-1, 1/2)