What is the extreme f(x)=x^3+x^2-8x+5 ?

The extreme f(x)=x^3+x^2-8x+5 is Maximum(-2,17),Minimum(4/3 ,-41/27)

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extreme f(x)=x^3+x^2-8x+5

extreme points

f (x) = x^{3} + x^{2} - 8 x + 5

Maximum (- 2, 17), Minimum (\frac{4}{3}, - \frac{41}{27})

Solution steps

f^{'} (x) = 3 x^{2} + 2 x - 8

Find intervals:

Increasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < \frac{4}{3},

Increasing

: \frac{4}{3} < x < \infty

Plug

x = - 2

into

x^{3} + x^{2} - 8 x + 5 : 17

Maximum (- 2, 17)

Plug

x = \frac{4}{3}

into

x^{3} + x^{2} - 8 x + 5 : - \frac{41}{27}

Minimum (\frac{4}{3}, - \frac{41}{27})

Maximum (- 2, 17), Minimum (\frac{4}{3}, - \frac{41}{27})

f (x) = \frac{x ^{2}}{x ^{2} - 4}

f (x, y) = 2 x^{2} + x y^{2} - 6 x y + 5 x + 2

f (x) = 3 x^{4} - 4 x^{3} + 2

f (x, y) = x y (1 - x - y)

f (x) = \frac{x ^{2} - 3}{x - 2}

What is the extreme f(x)=x^3+x^2-8x+5 ?
The extreme f(x)=x^3+x^2-8x+5 is Maximum(-2,17),Minimum(4/3 ,-41/27)