What is the domain of (\sqrt[3]{8-x})/(ln(x-4)) ?

The domain of (\sqrt[3]{8-x})/(ln(x-4)) is 4 5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of (\sqrt[3]{8-x})/(ln(x-4))

domain

4 < x < 5 or x > 5

Interval Notation

(4, 5) \cup (5, \infty)

Solution steps

Find positive values for logs:

x > 4

Find undefined (singularity) points:

x = 5

Combine real regions and undefined points for final function domain

4 < x < 5 or x > 5

f (x) = x^{2} + y^{2} x^{2} - 4 y^{2} = 0

f (x) = \frac{x}{x ^{2} - x + 1}

\frac{x ^{2} - x - 20}{x ^{2} - 4}

y = 1 x + 3, (- 7, 0)

f (x) = \frac{5 x + 1}{x - 2}

What is the domain of (\sqrt[3]{8-x})/(ln(x-4)) ?
The domain of (\sqrt[3]{8-x})/(ln(x-4)) is 4<x<5\lor x>5