What is the extreme (x^2-3x+5)e^{-x/3} ?

The extreme (x^2-3x+5)e^{-x/3} is Minimum(2, 3/(e^{2/3)}),Maximum(7,(33)/(e^{7/3)})

Popular >

extreme (x^2-3x+5)e^{-x/3}

extreme points

(x^{2} - 3 x + 5) e^{- \frac{x}{3}}

Minimum (2, \frac{3}{e ^{\frac{2}{3}}}), Maximum (7, \frac{33}{e ^{\frac{7}{3}}})

Solution steps

f^{'} (x) = e^{- \frac{x}{3}} (\frac{- x ^{2} - 5}{3} + 3 x - 3)

Find intervals:

Decreasing

: - \infty < x < 2,

Increasing

: 2 < x < 7,

Decreasing

: 7 < x < \infty

Plug

x = 2

into

(x^{2} - 3 x + 5) e^{- \frac{x}{3}} : \frac{3}{e ^{\frac{2}{3}}}

Minimum (2, \frac{3}{e ^{\frac{2}{3}}})

Plug

x = 7

into

(x^{2} - 3 x + 5) e^{- \frac{x}{3}} : \frac{33}{e ^{\frac{7}{3}}}

Maximum (7, \frac{33}{e ^{\frac{7}{3}}})

Minimum (2, \frac{3}{e ^{\frac{2}{3}}}), Maximum (7, \frac{33}{e ^{\frac{7}{3}}})

f (x, y) = x y - 2 x - 2 y - x^{2} - y^{2}

f (x) = y^{3} + 3 x^{2} y - 6 x^{2} - 6 y^{2} + 2

f (x) = \frac{e ^{x}}{1 - e ^{x}}

f (x, y) = x^{3} - 12 x y + 8 y^{3}

f (x, y) = ln (x^{2} + y^{2} + 1)

What is the extreme (x^2-3x+5)e^{-x/3} ?
The extreme (x^2-3x+5)e^{-x/3} is Minimum(2, 3/(e^{2/3)}),Maximum(7,(33)/(e^{7/3)})