What is the extreme f(x)=x^5ln(x) ?

The extreme f(x)=x^5ln(x) is Minimum(1/(\sqrt[5]{e)},-1/(5e))

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extreme f(x)=x^5ln(x)

extreme points

f (x) = x^{5} ln (x)

Solution steps

f^{'} (x) = 5 x^{4} ln (x) + x^{4}

Find intervals:

Decreasing

Increasing

Plug

into

x^{5} ln (x) : - \frac{1}{5 e}

f (x, y) = - x^{3} + 4 x y - 2 y^{2} + 1

f (x) = \frac{( x + 1 ) ^{2}}{x}

\frac{d}{d B} (a (B - h))

f (x, y) = 2 x + y

f (x) = 2 x^{3} + x y^{2} + 5 x^{2} + y^{2}

What is the extreme f(x)=x^5ln(x) ?
The extreme f(x)=x^5ln(x) is Minimum(1/(\sqrt[5]{e)},-1/(5e))