What is the extreme f(x)=x^3-6x^2+9x+3 ?

The extreme f(x)=x^3-6x^2+9x+3 is Maximum(1,7),Minimum(3,3)

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extreme f(x)=x^3-6x^2+9x+3

extreme points

f (x) = x^{3} - 6 x^{2} + 9 x + 3

Maximum (1, 7), Minimum (3, 3)

Solution steps

f^{'} (x) = 3 x^{2} - 12 x + 9

Find intervals:

Increasing

: - \infty < x < 1,

Decreasing

: 1 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = 1

into

x^{3} - 6 x^{2} + 9 x + 3 : 7

Maximum (1, 7)

Plug

x = 3

into

x^{3} - 6 x^{2} + 9 x + 3 : 3

Minimum (3, 3)

Maximum (1, 7), Minimum (3, 3)

x - 2 + 4 - x

f (x, y) = y e^{x} - 2 e^{x} - e^{y} + 5

f (x, y) = e^{2 x y}

f (x, y) = ln ∣ x + e^{y} ∣ - sin (5 x y^{2})

f (x) = 3 x e^{x}

What is the extreme f(x)=x^3-6x^2+9x+3 ?
The extreme f(x)=x^3-6x^2+9x+3 is Maximum(1,7),Minimum(3,3)