What is the extreme f(x)= 1/3 x^3-9x+2 ?

The extreme f(x)= 1/3 x^3-9x+2 is Maximum(-3,20),Minimum(3,-16)

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extreme f(x)= 1/3 x^3-9x+2

extreme points

f (x) = \frac{1}{3} x^{3} - 9 x + 2

Maximum (- 3, 20), Minimum (3, - 16)

Solution steps

f^{'} (x) = x^{2} - 9

Find intervals:

Increasing

: - \infty < x < - 3,

Decreasing

: - 3 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = - 3

into

\frac{1}{3} x^{3} - 9 x + 2 : 20

Maximum (- 3, 20)

Plug

x = 3

into

\frac{1}{3} x^{3} - 9 x + 2 : - 16

Minimum (3, - 16)

Maximum (- 3, 20), Minimum (3, - 16)

f (x) = e^{x^{2} - 7 x - 1}

f (x) = 25 - x^{2} - y^{2}

f (x) = \frac{x ^{2} + 2 x + 1}{x}

f (x) = x^{2} - 1

f (x) = x^{\frac{2}{3}} - 3

What is the extreme f(x)= 1/3 x^3-9x+2 ?
The extreme f(x)= 1/3 x^3-9x+2 is Maximum(-3,20),Minimum(3,-16)