What is the extreme f(x)=-x^4+6x^2-4 ?

The extreme f(x)=-x^4+6x^2-4 is Maximum(-sqrt(3),5),Minimum(0,-4),Maximum(sqrt(3),5)

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extreme f(x)=-x^4+6x^2-4

extreme points

f (x) = - x^{4} + 6 x^{2} - 4

Maximum (- 3, 5), Minimum (0, - 4), Maximum (3, 5)

Solution steps

f^{'} (x) = - 4 x^{3} + 12 x

Find intervals:

Increasing

: - \infty < x < - 3,

Decreasing

: - 3 < x < 0,

Increasing

: 0 < x < 3,

Decreasing

: 3 < x < \infty

Plug

x = - 3

into

- x^{4} + 6 x^{2} - 4 : 5

Maximum (- 3, 5)

Plug

x = 0

into

- x^{4} + 6 x^{2} - 4 : - 4

Minimum (0, - 4)

Plug

x = 3

into

- x^{4} + 6 x^{2} - 4 : 5

Maximum (3, 5)

Maximum (- 3, 5), Minimum (0, - 4), Maximum (3, 5)

f (x) = 3 x^{4} - 4 x^{3} + 1

f (x, y) = x^{3} + 3 x y^{2} - 15 x - 12 y

f (x) = 1 - x^{2} - y^{2}

f (x) = sin (x) - cos (x)

f (x, y) = x^{2} - y^{2} 1 - x^{2} - y^{2}

What is the extreme f(x)=-x^4+6x^2-4 ?
The extreme f(x)=-x^4+6x^2-4 is Maximum(-sqrt(3),5),Minimum(0,-4),Maximum(sqrt(3),5)