What is the extreme f(x,y)=y^2e^{-x+ln(y)} ?

The extreme f(x,y)=y^2e^{-x+ln(y)} is None

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extreme f(x,y)=y^2e^{-x+ln(y)}

extreme points

f (x, y) = y^{2} e^{- x + l n (y)}

None

Solution steps

Find the critical points:

None

y^{2} e^{- x + l n (y)}

has no critical points, therefore there are no extreme points

None

f (x, y) = x^{3} + y^{3} - 15 x y

f (x, y) = 49 - x^{2} - y^{2}

f (x) = \frac{1}{2} x^{4} - 3 x y + 3 y^{4}

f (x, y) = x y + y^{2} e^{2 x}

3 x^{5} - 5 x^{3}

What is the extreme f(x,y)=y^2e^{-x+ln(y)} ?
The extreme f(x,y)=y^2e^{-x+ln(y)} is None