What is the extreme f(x)=x^3-6x^2+10 ?

The extreme f(x)=x^3-6x^2+10 is Maximum(0,10),Minimum(4,-22)

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extreme f(x)=x^3-6x^2+10

extreme points

f (x) = x^{3} - 6 x^{2} + 10

Maximum (0, 10), Minimum (4, - 22)

Solution steps

f^{'} (x) = 3 x^{2} - 12 x

Find intervals:

Increasing

: - \infty < x < 0,

Decreasing

: 0 < x < 4,

Increasing

: 4 < x < \infty

Plug

x = 0

into

x^{3} - 6 x^{2} + 10 : 10

Maximum (0, 10)

Plug

x = 4

into

x^{3} - 6 x^{2} + 10 : - 22

Minimum (4, - 22)

Maximum (0, 10), Minimum (4, - 22)

f (x) = \frac{1}{1 + e ^{- x}}

f (x, y) = 3 + 1 - \frac{( x - 2 ) ^{2}}{4} - \frac{( y - 3 ) ^{2}}{9}

f (x) = \frac{x ^{2}}{2} + \frac{1}{3} x

y = x^{4} - 4 x^{3}

f (x) = 2 + 3 x - x^{3}

What is the extreme f(x)=x^3-6x^2+10 ?
The extreme f(x)=x^3-6x^2+10 is Maximum(0,10),Minimum(4,-22)