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Popular >

extreme f(x)=(x^2)/(x^2+1)

Solution

extreme points

f (x) = \frac{x ^{2}}{x ^{2} + 1}

Solution

Minimum (0, 0)

Solution steps

f^{'} (x) = \frac{2 x}{( x ^{2} + 1 ) ^{2}}

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

\frac{x ^{2}}{x ^{2} + 1} : 0

Minimum (0, 0)

Popular Examples

extreme f(x,y)=7+x+4y-x^2-4y^2 extreme points

f (x, y) = 7 + x + 4 y - x^{2} - 4 y^{2}

extreme f(x)=2x^3-6x+6xy^2 extreme points

f (x) = 2 x^{3} - 6 x + 6 x y^{2}

extreme f(x,y)=5+4x+6y extreme points

f (x, y) = 5 + 4 x + 6 y

extreme f(x,y)=(2x-y)/((x-2)^2+(y-1)^2)extreme points

f (x, y) = \frac{2 x - y}{( x - 2 ) ^{2} + ( y - 1 ) ^{2}}

extreme f(x)= x/((x^2+1))extreme points

f (x) = \frac{x}{( x ^{2} + 1 )}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=(x^2)/(x^2+1) ?
The extreme f(x)=(x^2)/(x^2+1) is Minimum(0,0)