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Popular >

extreme f(x)=(x-2)^4

Solution

extreme points

f (x) = (x - 2)^{4}

Solution

Minimum (2, 0)

Solution steps

f^{'} (x) = 4 (x - 2)^{3}

Find intervals:

Decreasing

: - \infty < x < 2,

Increasing

: 2 < x < \infty

Plug

x = 2

into

(x - 2)^{4} : 0

Minimum (2, 0)

Popular Examples

extreme f(x)=10+4x+9/x extreme points

f (x) = 10 + 4 x + \frac{9}{x}

extreme f(x)=8x^3-17x^2+12x+14 extreme points

f (x) = 8 x^{3} - 17 x^{2} + 12 x + 14

extreme f(x,y)=3y^3+7xy-9x^2-5 extreme points

f (x, y) = 3 y^{3} + 7 x y - 9 x^{2} - 5

extreme f(x)=-(cos(2x))/2-2sin(x)extreme points

f (x) = - \frac{cos ( 2 x )}{2} - 2 sin (x)

extreme f(x,y)=ln(x+y)+x^2-y extreme points

f (x, y) = ln (x + y) + x^{2} - y

Frequently Asked Questions (FAQ)

What is the extreme f(x)=(x-2)^4 ?
The extreme f(x)=(x-2)^4 is Minimum(2,0)