What is the domain of f(x)=((x+2))/(x-1) ?

The domain of f(x)=((x+2))/(x-1) is x 1

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domain of f(x)=((x+2))/(x-1)

domain

f (x) = \frac{( x + 2 )}{x - 1}

x < 1 or x > 1

Interval Notation

(- \infty, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1

The function domain

x < 1 or x > 1

(0, 4), (1, 4)

x^{2} + 3 x + 6

f (x) = x^{2} - 16

f (x) = \frac{x}{x ^{2} - x}

y = - 8 x + 7, (- 6, - 4)

What is the domain of f(x)=((x+2))/(x-1) ?
The domain of f(x)=((x+2))/(x-1) is x<1\lor x>1