What is the extreme f(x,y)=(5x+3y+10)(4y+2) ?

The extreme f(x,y)=(5x+3y+10)(4y+2) is Saddle(-17/10 ,-1/2)

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extreme f(x,y)=(5x+3y+10)(4y+2)

extreme points

f (x, y) = (5 x + 3 y + 10) (4 y + 2)

Saddle (- \frac{17}{10}, - \frac{1}{2})

Solution steps

Find the critical points:

(- \frac{17}{10}, - \frac{1}{2})

\frac{\partial ^{2} f}{\partial x ^{2}} = 24

D (x, y) = - 400

Check the sign of at each critical point

Check critical point

(- \frac{17}{10}, - \frac{1}{2}) :

Saddle

Saddle (- \frac{17}{10}, - \frac{1}{2})

f (x) = x^{3} - 9 x

f (x, y) = x^{2} - 2 x y + 1

f (x) = 3 x^{2} y + y^{3} - 3 x^{2} - 3 y^{2} + 2

f (x) = x^{4} + 4 x

f (x, y) = - 3 x y + x^{3} - y^{3} + \frac{1}{8}

What is the extreme f(x,y)=(5x+3y+10)(4y+2) ?
The extreme f(x,y)=(5x+3y+10)(4y+2) is Saddle(-17/10 ,-1/2)