What is the extreme f(x)=x^3-3x^2-24x+1 ?

The extreme f(x)=x^3-3x^2-24x+1 is Maximum(-2,29),Minimum(4,-79)

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extreme f(x)=x^3-3x^2-24x+1

extreme points

f (x) = x^{3} - 3 x^{2} - 24 x + 1

Maximum (- 2, 29), Minimum (4, - 79)

Solution steps

f^{'} (x) = 3 x^{2} - 6 x - 24

Find intervals:

Increasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < 4,

Increasing

: 4 < x < \infty

Plug

x = - 2

into

x^{3} - 3 x^{2} - 24 x + 1 : 29

Maximum (- 2, 29)

Plug

x = 4

into

x^{3} - 3 x^{2} - 24 x + 1 : - 79

Minimum (4, - 79)

Maximum (- 2, 29), Minimum (4, - 79)

f (x) = x^{2} - 2 x + 4

f (x, y) = \frac{x y}{1 + e ^{x - y}}

f (x) = - x^{3} + 4 x y - 2 y^{2} + 1

f (x, y) = x^{3} + y^{3} - 18 x y

f (x) = x^{2} + \frac{8}{x}

What is the extreme f(x)=x^3-3x^2-24x+1 ?
The extreme f(x)=x^3-3x^2-24x+1 is Maximum(-2,29),Minimum(4,-79)