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Popular >

extreme y=3x^2+12x

Solution

extreme points

y = 3 x^{2} + 12 x

Solution

Minimum (- 2, - 12)

Solution steps

f^{'} (x) = 6 x + 12

Find intervals:

Decreasing

: - \infty < x < - 2,

Increasing

: - 2 < x < \infty

Plug

x = - 2

into

3 x^{2} + 12 x : - 12

Minimum (- 2, - 12)

Popular Examples

extreme f(x)=-2x^3+12x^2+18 extreme points

f (x) = - 2 x^{3} + 12 x^{2} + 18

extreme f(x)=-x^3+3x^2 extreme points

f (x) = - x^{3} + 3 x^{2}

extreme f(x,y)=3-x^2-y^2 extreme points

f (x, y) = 3 - x^{2} - y^{2}

extreme f(x,y)=2xy-5x^2-2y^2+18y-8 extreme points

f (x, y) = 2 x y - 5 x^{2} - 2 y^{2} + 18 y - 8

extreme f(x)=(x+1)^{2/3}(x-3)^2 extreme points

f (x) = (x + 1)^{\frac{2}{3}} (x - 3)^{2}

Frequently Asked Questions (FAQ)

What is the extreme y=3x^2+12x ?
The extreme y=3x^2+12x is Minimum(-2,-12)