What is the extreme f(x)=log_{2}((2-3x)/(3-x)) ?

The extreme f(x)=log_{2}((2-3x)/(3-x)) is None

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extreme f(x)=log_{2}((2-3x)/(3-x))

extreme points

f (x) = lo g_{2} (\frac{2 - 3 x}{3 - x})

None

Solution steps

f^{'} (x) = - \frac{7}{ln ( 2 ) ( - 3 x + 2 ) ( - x + 3 )}

Find intervals:

None

None

f (x, y) = - x^{2} - 5 y^{2} + 8 x - 10 y

f (x) = x^{3} + x^{2} - x + 1

f (x) = 3 x^{2} - 150 ln (x)

F (x, y) = x^{3} - 6 x y + 3 y^{2} + 1

f (x) = x^{3} - \frac{3 x ^{2}}{2} + 3

What is the extreme f(x)=log_{2}((2-3x)/(3-x)) ?
The extreme f(x)=log_{2}((2-3x)/(3-x)) is None