What is the extreme f(x)=x^3-6x^2+9x+15 ?

The extreme f(x)=x^3-6x^2+9x+15 is Maximum(1,19),Minimum(3,15)

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extreme f(x)=x^3-6x^2+9x+15

extreme points

f (x) = x^{3} - 6 x^{2} + 9 x + 15

Maximum (1, 19), Minimum (3, 15)

Solution steps

f^{'} (x) = 3 x^{2} - 12 x + 9

Find intervals:

Increasing

: - \infty < x < 1,

Decreasing

: 1 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = 1

into

x^{3} - 6 x^{2} + 9 x + 15 : 19

Maximum (1, 19)

Plug

x = 3

into

x^{3} - 6 x^{2} + 9 x + 15 : 15

Minimum (3, 15)

Maximum (1, 19), Minimum (3, 15)

f (x, y) = 2 x + 2 x y + y

x^{2} y - x^{2} - 2 y^{2}

f (x) = 3 - 4 sin (3 x)

f (x, y) = ln ∣ 4 - x - y ∣

f (x) = (x^{2} - 1)^{4}

What is the extreme f(x)=x^3-6x^2+9x+15 ?
The extreme f(x)=x^3-6x^2+9x+15 is Maximum(1,19),Minimum(3,15)