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Popular >

extreme f(x)=x^2+2x-6

Solution

extreme points

f (x) = x^{2} + 2 x - 6

Solution

Minimum (- 1, - 7)

Solution steps

f^{'} (x) = 2 x + 2

Find intervals:

Decreasing

: - \infty < x < - 1,

Increasing

: - 1 < x < \infty

Plug

x = - 1

into

x^{2} + 2 x - 6 : - 7

Minimum (- 1, - 7)

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extreme f(x)=5+54x-2x^3 extreme points

f (x) = 5 + 54 x - 2 x^{3}

extreme f(x,y)=x^2+2y^2+4xy+2x+4y extreme points

f (x, y) = x^{2} + 2 y^{2} + 4 x y + 2 x + 4 y

extreme f(x,y)=2x^2+2xy+y^2+2x-3 extreme points

f (x, y) = 2 x^{2} + 2 x y + y^{2} + 2 x - 3

extreme K(y,z)=32yz extreme points

K (y, z) = 32 yz

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2+2x-6 ?
The extreme f(x)=x^2+2x-6 is Minimum(-1,-7)