What is the extreme f(x)=x^3-6x^2+9x-2 ?

The extreme f(x)=x^3-6x^2+9x-2 is Maximum(1,2),Minimum(3,-2)

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extreme f(x)=x^3-6x^2+9x-2

extreme points

f (x) = x^{3} - 6 x^{2} + 9 x - 2

Maximum (1, 2), Minimum (3, - 2)

Solution steps

f^{'} (x) = 3 x^{2} - 12 x + 9

Find intervals:

Increasing

: - \infty < x < 1,

Decreasing

: 1 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = 1

into

x^{3} - 6 x^{2} + 9 x - 2 : 2

Maximum (1, 2)

Plug

x = 3

into

x^{3} - 6 x^{2} + 9 x - 2 : - 2

Minimum (3, - 2)

Maximum (1, 2), Minimum (3, - 2)

f (x) = \frac{x}{x ^{2} - x + 9}

f (x, y) = ∣ x ∣ + y^{2} - 1

E, E = I R

f (x) = x^{2} - 4 x - 5

f (x, y) = x^{2} - 4 x y + y^{2} + 6 y + 2

What is the extreme f(x)=x^3-6x^2+9x-2 ?
The extreme f(x)=x^3-6x^2+9x-2 is Maximum(1,2),Minimum(3,-2)