What is the extreme f(x)=xsqrt(6-x) ?

The extreme f(x)=xsqrt(6-x) is Maximum(4,4sqrt(2)),Minimum(6,0)

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extreme f(x)=xsqrt(6-x)

extreme points

f (x) = x 6 - x

Maximum (4, 42), Minimum (6, 0)

Solution steps

f^{'} (x) = - \frac{3 ( x - 4 )}{2 6 - x}

Find intervals:

Increasing

: - \infty < x < 4,

Decreasing

: 4 < x < 6

Plug

x = 4

into

x 6 - x : 42

Maximum (4, 42)

Plug

x = 6

into

x 6 - x : 0

Minimum (6, 0)

Maximum (4, 42), Minimum (6, 0)

f (x, y) = x^{3} + y^{3} - 12 x y

f (x, y) = x^{2} + x y + 3 x + 2 y + 5

f (x) = x^{4} + 2 x^{2} - 3, - 2 \leq x \leq 2

P (a, b) = a^{3} - b^{3} + a^{2} + ab + b^{2}

f (x) = 8 x^{3} + 81 x^{2} - 42 x - 8

What is the extreme f(x)=xsqrt(6-x) ?
The extreme f(x)=xsqrt(6-x) is Maximum(4,4sqrt(2)),Minimum(6,0)