What is the extreme f(x)=x+(36)/x ?

The extreme f(x)=x+(36)/x is Maximum(-6,-12),Minimum(6,12)

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extreme f(x)=x+(36)/x

extreme points

f (x) = x + \frac{36}{x}

Maximum (- 6, - 12), Minimum (6, 12)

Solution steps

f^{'} (x) = 1 - \frac{36}{x ^{2}}

Find intervals:

Increasing

: - \infty < x < - 6,

Decreasing

: - 6 < x < 0,

Decreasing

: 0 < x < 6,

Increasing

: 6 < x < \infty

Plug

x = - 6

into

x + \frac{36}{x} : - 12

Maximum (- 6, - 12)

Plug

x = 6

into

x + \frac{36}{x} : 12

Minimum (6, 12)

Maximum (- 6, - 12), Minimum (6, 12)

f (x) = \frac{x}{x ^{2} - x + 9}, 0 \leq x \leq 9

f (x) = e^{x^{2} - 3 x - 1}

f (x) = 3 x^{4} + 16 x^{3}

f (x) = (x^{2} - 3)^{2}

f (x) = (x - 1) e^{x}

What is the extreme f(x)=x+(36)/x ?
The extreme f(x)=x+(36)/x is Maximum(-6,-12),Minimum(6,12)