What is the extreme f(x,y)=-x^2-y^2+8x+6y ?

The extreme f(x,y)=-x^2-y^2+8x+6y is Maximum(4,3)

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extreme f(x,y)=-x^2-y^2+8x+6y

extreme points

f (x, y) = - x^{2} - y^{2} + 8 x + 6 y

Maximum (4, 3)

Solution steps

Find the critical points:

(4, 3)

\frac{\partial ^{2} f}{\partial x ^{2}} = - 2

D (x, y) = 4

Check the sign of at each critical point

Check critical point

(4, 3) :

Maximum

Maximum (4, 3)

f (x) = x + e^{- 2 x}

f (x) = \frac{x + 1}{x ^{2} + x + 1}

f (x) = - x (x + 2) (x - 2)

f (x) = 3 x^{4} - 4 x^{3} - 12 x^{2} + 5

f (x) = x^{3} + x^{2} - 5 x + 3

What is the extreme f(x,y)=-x^2-y^2+8x+6y ?
The extreme f(x,y)=-x^2-y^2+8x+6y is Maximum(4,3)