en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=4x^2-4x+1

Solution

extreme points

f (x) = 4 x^{2} - 4 x + 1

Solution

Minimum (\frac{1}{2}, 0)

Solution steps

f^{'} (x) = 8 x - 4

Find intervals:

Decreasing

: - \infty < x < \frac{1}{2},

Increasing

: \frac{1}{2} < x < \infty

Plug

x = \frac{1}{2}

into

4 x^{2} - 4 x + 1 : 0

Minimum (\frac{1}{2}, 0)

Popular Examples

extreme y=x^3-3x^2 extreme points

y = x^{3} - 3 x^{2}

extreme f(x)= 2/5 x^5+5x^4+16x^3-15 extreme points

f (x) = \frac{2}{5} x^{5} + 5 x^{4} + 16 x^{3} - 15

extreme f(x)=x^3-3x^2+6 extreme points

f (x) = x^{3} - 3 x^{2} + 6

extreme f(x,y)=x^2+y^2-2x-6y+14 extreme points

f (x, y) = x^{2} + y^{2} - 2 x - 6 y + 14

extreme f(x,y)=x^3-y^3-2xy+6 extreme points

f (x, y) = x^{3} - y^{3} - 2 x y + 6

Frequently Asked Questions (FAQ)

What is the extreme f(x)=4x^2-4x+1 ?
The extreme f(x)=4x^2-4x+1 is Minimum(1/2 ,0)