What is the extreme f(x,y)=x^2-xy ?

The extreme f(x,y)=x^2-xy is Saddle(0,0)

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extreme f(x,y)=x^2-xy

extreme points

f (x, y) = x^{2} - x y

Saddle (0, 0)

Solution steps

Find the critical points:

(0, 0)

\frac{\partial ^{2} f}{\partial x ^{2}} = 0

D (x, y) = - 1

Check the sign of at each critical point

Check critical point

(0, 0) :

Saddle

Saddle (0, 0)

f (x) = sec (x)

f (x, y) = ye x + 2 x ey - 1

f (x, y) = 7 y - 4 (x + y)^{2}

f (x, y) = \frac{1}{x - y}

f (x) = 4 x^{5} - 5 x^{4}