What is the extreme f(x)=2x^3-9x^2+27 ?

The extreme f(x)=2x^3-9x^2+27 is Maximum(0,27),Minimum(3,0)

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extreme f(x)=2x^3-9x^2+27

extreme points

f (x) = 2 x^{3} - 9 x^{2} + 27

Maximum (0, 27), Minimum (3, 0)

Solution steps

f^{'} (x) = 6 x^{2} - 18 x

Find intervals:

Increasing

: - \infty < x < 0,

Decreasing

: 0 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = 0

into

2 x^{3} - 9 x^{2} + 27 : 27

Maximum (0, 27)

Plug

x = 3

into

2 x^{3} - 9 x^{2} + 27 : 0

Minimum (3, 0)

Maximum (0, 27), Minimum (3, 0)

f (x, y) = x^{2} - x^{2} y^{2} + y^{2}

f (x, y) = x^{2} y + 4 x y - 2 y^{2} - 3

f (x) = \frac{1 - x ^{2}}{1 + x ^{2}}

f (x, y) = 3 x^{2} + 2 y^{2}

f (x) = - \frac{3}{5} x^{5} + 9 x^{4} - 35 x^{3} + 6

What is the extreme f(x)=2x^3-9x^2+27 ?
The extreme f(x)=2x^3-9x^2+27 is Maximum(0,27),Minimum(3,0)