What is the inverse of f(x)=\sqrt[5]{x^3+2}-1 ?

The inverse of f(x)=\sqrt[5]{x^3+2}-1 is cube root of x^5+5x^4+10x^3+10x^2+5x-1

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inverse of f(x)=\sqrt[5]{x^3+2}-1

inverse

Solution steps

Replace

x

with

y

Solve for

f (x) = 4 x^{4} - 20 x^{3} - 3 x^{2} + 14 x + 5

y = cot (\frac{1}{9} x)

f (x) = \frac{4 x}{x ^{2} - 16}

\frac{x ^{2} - 25}{x + 5}

f (x) = 1 0^{x} = 11

What is the inverse of f(x)=\sqrt[5]{x^3+2}-1 ?
The inverse of f(x)=\sqrt[5]{x^3+2}-1 is cube root of x^5+5x^4+10x^3+10x^2+5x-1