What is the extreme f(x)=x+(64)/x ?

The extreme f(x)=x+(64)/x is Maximum(-8,-16),Minimum(8,16)

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extreme f(x)=x+(64)/x

extreme points

f (x) = x + \frac{64}{x}

Maximum (- 8, - 16), Minimum (8, 16)

Solution steps

f^{'} (x) = 1 - \frac{64}{x ^{2}}

Find intervals:

Increasing

: - \infty < x < - 8,

Decreasing

: - 8 < x < 0,

Decreasing

: 0 < x < 8,

Increasing

: 8 < x < \infty

Plug

x = - 8

into

x + \frac{64}{x} : - 16

Maximum (- 8, - 16)

Plug

x = 8

into

x + \frac{64}{x} : 16

Minimum (8, 16)

Maximum (- 8, - 16), Minimum (8, 16)

f (x) = x^{3} - \frac{3}{2} x^{2}, - 1 \leq x \leq 2

f (x) = x^{2} + x - 2

f (x, y) = y^{3} + 9 y^{2} - 8 x y + 5 x^{2} - 2

\frac{e ^{- x}}{x + 1}

\frac{x}{1 + x}

What is the extreme f(x)=x+(64)/x ?
The extreme f(x)=x+(64)/x is Maximum(-8,-16),Minimum(8,16)