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Popular >

extreme f(x)=(-8)/(x^2-4)

Solution

extreme points

f (x) = \frac{- 8}{x ^{2} - 4}

Solution

Minimum (0, 2)

Solution steps

f^{'} (x) = \frac{16 x}{( x ^{2} - 4 ) ^{2}}

Find intervals:

Decreasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < 0,

Increasing

: 0 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = 0

into

\frac{- 8}{x ^{2} - 4} : 2

Minimum (0, 2)

Popular Examples

extreme f(x)=(x^2-x-2)/(x^2-6x+9)extreme points

f (x) = \frac{x ^{2} - x - 2}{x ^{2} - 6 x + 9}

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f (x) = \frac{x - 1}{x ^{2}}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=(-8)/(x^2-4) ?
The extreme f(x)=(-8)/(x^2-4) is Minimum(0,2)