What is the extreme f(x)=x^3+7x^2-5x ?

The extreme f(x)=x^3+7x^2-5x is Maximum(-5,75),Minimum(1/3 ,-23/27)

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extreme f(x)=x^3+7x^2-5x

extreme points

f (x) = x^{3} + 7 x^{2} - 5 x

Maximum (- 5, 75), Minimum (\frac{1}{3}, - \frac{23}{27})

Solution steps

f^{'} (x) = 3 x^{2} + 14 x - 5

Find intervals:

Increasing

: - \infty < x < - 5,

Decreasing

: - 5 < x < \frac{1}{3},

Increasing

: \frac{1}{3} < x < \infty

Plug

x = - 5

into

x^{3} + 7 x^{2} - 5 x : 75

Maximum (- 5, 75)

Plug

x = \frac{1}{3}

into

x^{3} + 7 x^{2} - 5 x : - \frac{23}{27}

Minimum (\frac{1}{3}, - \frac{23}{27})

Maximum (- 5, 75), Minimum (\frac{1}{3}, - \frac{23}{27})

f (x) = x^{4} - 4 x^{3} + 9 x + 1

f (x, y) = 9 x^{3} + \frac{y ^{3}}{3} - 4 x y

f (x) = x + y

f (x) = (2 x - 2)^{3} (3 x - 1)^{2}

f (x) = x^{4} - 4 x^{3} - 8 x^{2}

What is the extreme f(x)=x^3+7x^2-5x ?
The extreme f(x)=x^3+7x^2-5x is Maximum(-5,75),Minimum(1/3 ,-23/27)