What is the extreme f(x)=x^3-3x^2+10 ?

The extreme f(x)=x^3-3x^2+10 is Maximum(0,10),Minimum(2,6)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=x^3-3x^2+10

extreme points

f (x) = x^{3} - 3 x^{2} + 10

Maximum (0, 10), Minimum (2, 6)

Solution steps

f^{'} (x) = 3 x^{2} - 6 x

Find intervals:

Increasing

: - \infty < x < 0,

Decreasing

: 0 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = 0

into

x^{3} - 3 x^{2} + 10 : 10

Maximum (0, 10)

Plug

x = 2

into

x^{3} - 3 x^{2} + 10 : 6

Minimum (2, 6)

Maximum (0, 10), Minimum (2, 6)

f (x) = (x^{2} - 3) e^{x}

y = x^{4} - 4 x^{3} + 2

\frac{x + 3}{x ^{2}}

f (x) = x y + \frac{1}{x} + \frac{1}{y}

y = x^{2} + z^{2}

What is the extreme f(x)=x^3-3x^2+10 ?
The extreme f(x)=x^3-3x^2+10 is Maximum(0,10),Minimum(2,6)