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Popular >

extreme f(x)=x^2+x

Solution

extreme points

f (x) = x^{2} + x

Solution

Minimum (- \frac{1}{2}, - \frac{1}{4})

Solution steps

f^{'} (x) = 2 x + 1

Find intervals:

Decreasing

: - \infty < x < - \frac{1}{2},

Increasing

: - \frac{1}{2} < x < \infty

Plug

x = - \frac{1}{2}

into

x^{2} + x : - \frac{1}{4}

Minimum (- \frac{1}{2}, - \frac{1}{4})

Popular Examples

extreme f(x)= x/(x^2-x+4),0<= x<= 6 extreme points

f (x) = \frac{x}{x ^{2} - x + 4}, 0 \leq x \leq 6

extreme f(x)=x^3-6x^2+11 extreme points

f (x) = x^{3} - 6 x^{2} + 11

extreme f(x,y)=6x-4y-x^2-2y^2 extreme points

f (x, y) = 6 x - 4 y - x^{2} - 2 y^{2}

extreme f(x,y)=10x^2y-5x^2-4y^2-x^4-2y^4 extreme points

f (x, y) = 10 x^{2} y - 5 x^{2} - 4 y^{2} - x^{4} - 2 y^{4}

extreme f(x,y)=xy^2+2xy+3x^3-3x extreme points

f (x, y) = x y^{2} + 2 x y + 3 x^{3} - 3 x

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2+x ?
The extreme f(x)=x^2+x is Minimum(-1/2 ,-1/4)