en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=(-6)/(x^2-9)

Solution

extreme points

f (x) = \frac{- 6}{x ^{2} - 9}

Solution

Minimum (0, \frac{2}{3})

Solution steps

f^{'} (x) = \frac{12 x}{( x ^{2} - 9 ) ^{2}}

Find intervals:

Decreasing

: - \infty < x < - 3,

Decreasing

: - 3 < x < 0,

Increasing

: 0 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = 0

into

\frac{- 6}{x ^{2} - 9} : \frac{2}{3}

Minimum (0, \frac{2}{3})

Popular Examples

extreme f(x)=(x-4)^4(x+3)^3 extreme points

f (x) = (x - 4)^{4} (x + 3)^{3}

extreme f(x)=2x^3-6x^2-48x+10 extreme points

f (x) = 2 x^{3} - 6 x^{2} - 48 x + 10

extreme f(x)=e^{6x}+e^{-x}extreme points

f (x) = e^{6 x} + e^{- x}

extreme f(x)=(sqrt(x))/(1+x)extreme points

f (x) = \frac{x}{1 + x}

extreme f(x)=x^2sqrt(x+5)extreme points

f (x) = x^{2} x + 5

Frequently Asked Questions (FAQ)

What is the extreme f(x)=(-6)/(x^2-9) ?
The extreme f(x)=(-6)/(x^2-9) is Minimum(0, 2/3)