What is the extreme f(x)=2x^3-3x^2-12x+3 ?

The extreme f(x)=2x^3-3x^2-12x+3 is Maximum(-1,10),Minimum(2,-17)

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extreme f(x)=2x^3-3x^2-12x+3

extreme points

f (x) = 2 x^{3} - 3 x^{2} - 12 x + 3

Maximum (- 1, 10), Minimum (2, - 17)

Solution steps

f^{'} (x) = 6 x^{2} - 6 x - 12

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = - 1

into

2 x^{3} - 3 x^{2} - 12 x + 3 : 10

Maximum (- 1, 10)

Plug

x = 2

into

2 x^{3} - 3 x^{2} - 12 x + 3 : - 17

Minimum (2, - 17)

Maximum (- 1, 10), Minimum (2, - 17)

f (x) = (x^{2} - 1) (x - 3)

f (x) = 3 x^{4}

f (x, y) = x^{3} + 3 y^{3} + 3 x^{2} + 3 y^{2} + 24

f (x) = 36 - 9 x^{2} - 4 y^{2}

f (x) = - x^{2} + x - y^{2} - 2 y

What is the extreme f(x)=2x^3-3x^2-12x+3 ?
The extreme f(x)=2x^3-3x^2-12x+3 is Maximum(-1,10),Minimum(2,-17)