en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme y=(x^2)/(x^2-1)

Solution

extreme points

y = \frac{x ^{2}}{x ^{2} - 1}

Solution

Maximum (0, 0)

Solution steps

f^{'} (x) = - \frac{2 x}{( x ^{2} - 1 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < - 1,

Increasing

: - 1 < x < 0,

Decreasing

: 0 < x < 1,

Decreasing

: 1 < x < \infty

Plug

x = 0

into

\frac{x ^{2}}{x ^{2} - 1} : 0

Maximum (0, 0)

Popular Examples

extreme f(x)=6x-4y-x^2-2y^2 extreme points

f (x) = 6 x - 4 y - x^{2} - 2 y^{2}

extreme f(x)=x^4-6x^2+9 extreme points

f (x) = x^{4} - 6 x^{2} + 9

extreme f(x)=-x^2+8x-15 extreme points

f (x) = - x^{2} + 8 x - 15

extreme f(x)=x^{4/5}(9-4x),0<= x<= 2 extreme points

f (x) = x^{\frac{4}{5}} (9 - 4 x), 0 \leq x \leq 2

extreme f(x)=-4x^2 extreme points

f (x) = - 4 x^{2}

Frequently Asked Questions (FAQ)

What is the extreme y=(x^2)/(x^2-1) ?
The extreme y=(x^2)/(x^2-1) is Maximum(0,0)