What is the extreme f(x)= 5/2 x-(x^2)/2 ?

The extreme f(x)= 5/2 x-(x^2)/2 is Maximum(5/2 , 25/8)

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extreme f(x)= 5/2 x-(x^2)/2

extreme points

f (x) = \frac{5}{2} x - \frac{x ^{2}}{2}

Maximum (\frac{5}{2}, \frac{25}{8})

Solution steps

f^{'} (x) = \frac{5}{2} - x

Find intervals:

Increasing

: - \infty < x < \frac{5}{2},

Decreasing

: \frac{5}{2} < x < \infty

Plug

x = \frac{5}{2}

into

\frac{5}{2} x - \frac{x ^{2}}{2} : \frac{25}{8}

Maximum (\frac{5}{2}, \frac{25}{8})

f (x, y) = ln (4 - x^{2} - y^{2})

f (x, y) = 6 y^{2} + 4 x^{2} - 12 x y - 4 y

f (x, y) = x^{2} + x y + y^{2} - 28 y + 261

f (x) = I x^{2} - 4 I

f (x) = \frac{x ^{3}}{3} - \frac{x ^{2}}{2} - 2 x

What is the extreme f(x)= 5/2 x-(x^2)/2 ?
The extreme f(x)= 5/2 x-(x^2)/2 is Maximum(5/2 , 25/8)