What is the extreme f(x)=x^3-3x^2-9x+20 ?

The extreme f(x)=x^3-3x^2-9x+20 is Maximum(-1,25),Minimum(3,-7)

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extreme f(x)=x^3-3x^2-9x+20

extreme points

f (x) = x^{3} - 3 x^{2} - 9 x + 20

Maximum (- 1, 25), Minimum (3, - 7)

Solution steps

f^{'} (x) = 3 x^{2} - 6 x - 9

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = - 1

into

x^{3} - 3 x^{2} - 9 x + 20 : 25

Maximum (- 1, 25)

Plug

x = 3

into

x^{3} - 3 x^{2} - 9 x + 20 : - 7

Minimum (3, - 7)

Maximum (- 1, 25), Minimum (3, - 7)

f (x) = \frac{2}{3} x^{3} + 3 x^{2} - 8 x + 1

f (x, y) = x^{3} + y^{3} - 3 x y + 4

y = x ln (x)

f (x) = x^{2} (x - 5)^{2}

f (x, y) = x y e^{x y}

What is the extreme f(x)=x^3-3x^2-9x+20 ?
The extreme f(x)=x^3-3x^2-9x+20 is Maximum(-1,25),Minimum(3,-7)