What is the extreme f(x,y)=5x^2+5y^2+20x-10y+40 ?

The extreme f(x,y)=5x^2+5y^2+20x-10y+40 is Minimum(-2,1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x,y)=5x^2+5y^2+20x-10y+40

extreme points

f (x, y) = 5 x^{2} + 5 y^{2} + 20 x - 10 y + 40

Minimum (- 2, 1)

Solution steps

Find the critical points:

(- 2, 1)

\frac{\partial ^{2} f}{\partial x ^{2}} = 10

D (x, y) = 100

Check the sign of at each critical point

Check critical point

(- 2, 1) :

Minimum

Minimum (- 2, 1)

y = 2 x + z

f (x) = x^{3} + x - 3

e^{x} (15 - x^{2})

f (x) = - \frac{2}{5} x^{5} - 5 x^{4} - 16 x^{3} - 5

g (x, y) = 16 - x^{2} + y^{2}

What is the extreme f(x,y)=5x^2+5y^2+20x-10y+40 ?
The extreme f(x,y)=5x^2+5y^2+20x-10y+40 is Minimum(-2,1)