en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=(x+2)^2

Solution

extreme points

f (x) = (x + 2)^{2}

Solution

Minimum (- 2, 0)

Solution steps

f^{'} (x) = 2 (x + 2)

Find intervals:

Decreasing

: - \infty < x < - 2,

Increasing

: - 2 < x < \infty

Plug

x = - 2

into

(x + 2)^{2} : 0

Minimum (- 2, 0)

Graph

Popular Examples

extreme f(x)=cos^2(x)-2sin(x)extreme points

f (x) = cos^{2} (x) - 2 sin (x)

extreme f(x)= x/(x^2+1),0<= x<= 2 extreme points

f (x) = \frac{x}{x ^{2} + 1}, 0 \leq x \leq 2

extreme f(x)=(x^3)/3-2x^2-12x extreme points

f (x) = \frac{x ^{3}}{3} - 2 x^{2} - 12 x

roots 10xy roots

10 x y

extreme f(x,y)=sqrt(64-x^2-y^2)extreme points

f (x, y) = 64 - x^{2} - y^{2}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=(x+2)^2 ?
The extreme f(x)=(x+2)^2 is Minimum(-2,0)