en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme (2x^2+5)/(x^2-25)

Solution

extreme points

\frac{2 x ^{2} + 5}{x ^{2} - 25}

Solution

Maximum (0, - \frac{1}{5})

Solution steps

f^{'} (x) = - \frac{110 x}{( x ^{2} - 25 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < - 5,

Increasing

: - 5 < x < 0,

Decreasing

: 0 < x < 5,

Decreasing

: 5 < x < \infty

Plug

x = 0

into

\frac{2 x ^{2} + 5}{x ^{2} - 25} : - \frac{1}{5}

Maximum (0, - \frac{1}{5})

Popular Examples

solvefor y,w=p(y-z)solve for

y, w = p (y - z)

extreme f(x,y)=sqrt(y)+sqrt(25-x^2-y^2)extreme points

f (x, y) = y + 25 - x^{2} - y^{2}

extreme f(x,y)=(1-x)(1-y)(x+y-1)extreme points

f (x, y) = (1 - x) (1 - y) (x + y - 1)

extreme f(x)=-6x^2+5xy-y^2+x+y extreme points

f (x) = - 6 x^{2} + 5 x y - y^{2} + x + y

extreme x^4-2x^2+3 extreme points

x^{4} - 2 x^{2} + 3

Frequently Asked Questions (FAQ)

What is the extreme (2x^2+5)/(x^2-25) ?
The extreme (2x^2+5)/(x^2-25) is Maximum(0,-1/5)