What is the extreme f(x)=x^3-12x^2 ?

The extreme f(x)=x^3-12x^2 is Maximum(0,0),Minimum(8,-256)

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extreme f(x)=x^3-12x^2

extreme points

f (x) = x^{3} - 12 x^{2}

Maximum (0, 0), Minimum (8, - 256)

Solution steps

f^{'} (x) = 3 x^{2} - 24 x

Find intervals:

Increasing

: - \infty < x < 0,

Decreasing

: 0 < x < 8,

Increasing

: 8 < x < \infty

Plug

x = 0

into

x^{3} - 12 x^{2} : 0

Maximum (0, 0)

Plug

x = 8

into

x^{3} - 12 x^{2} : - 256

Minimum (8, - 256)

Maximum (0, 0), Minimum (8, - 256)

f (x) = 2 x^{3} + 3 x^{2} - 336 x

y = x^{4} + 6 x^{3} + 12 x^{2} + 8 x + 10

f (x, y) = x^{2} - 2 x y + 3 y^{2}

f (x) = \frac{e ^{x}}{1 + x ^{2}}

f (x, y) = 6 x y - 2 x^{2} y - 3 x y^{2}

What is the extreme f(x)=x^3-12x^2 ?
The extreme f(x)=x^3-12x^2 is Maximum(0,0),Minimum(8,-256)